MCB Lec 10

the study of reaction rates that are catalyzed by a purified enzyme

V0= (vmax[S]) / (Km + [S])

forward is K1, backward is K-1
E+S <---> ES

kCat (turnover number)
ES --> E+P

tighter and higher affinity for ES

# of molecules in a given time when enzyme is saturated with substrate

constant

Km= (k-1+ kcat) / k1

Y intercept = 1 / (V max)
X intercept = - 1 / Km

leads to enzyme being idle

max velocity

substrate concentration that is needed to achieve half of Vmax

The ratio Kcat/Km combines information about how fast bound substrate is processed and how well substrate is captured

- every collision between enzyme and its substrate is productive
- the rate is only limited by the frequency of collision between the enzyme and its substrates