Additional Formulas

$F=\frac{1}{T}$
$F=\frac{\omega}{2π}

$\omega_{cr}=\sqrt{\frac{576EIg}{\omega L³}}

$I_M=\frac{1}{2}mr²$
$m=\rho V$
$V=At

$I_M=mk²

$k=\frac{r}{2}

$KE_r=\frac{1}{2}I\omega²

$IMA=\frac{2πL}{P}

$P_{design}=P_{gen}×ServiceFactor

$S=t+B

$f=\frac{1}{2π}\sqrt{\frac{k×12×32.2}{m}}

$AMA=\frac{1}{\frac{H}{L}+\frac{F_f}{W}}

$Tolerance=D_{max}-D_{min}

$\delta=\frac{4FL³}{Ebt²n}

$FS=\frac{F_{holding}}{F_{developed}}

$sin\alpha=\frac{}{}

$P=\frac{DNd^{2.3}}{50}

$No.Screw=\frac{P_{transmitted}}{P_{perscrew}}

$D_o=\left[\frac{1+\sqrt{2}}{2}\right]D_s

$v=\sqrt{kS_t}

$m=\rho V$
$V=Area×Thickness

$S=\frac{F}{\frac{\sqrt{2}}{2}tL}

$S_s=\frac{F}{\frac{1}{2}πDL}

$e=\frac{WL}{F(2πr)}

$W=S_t(0.55d²-0.25d)

$D=4.0⁴\sqrt{\frac{P}{N}}

$S=\frac{1}{cos\theta}-(tan\theta-rad)

$I=tan\theta-rad

$L_{10}=\frac{16667}{N}\left(\frac{C}{P}\right)^3$
$L_{10}=\frac{16667}{N}\left(\frac{C}{P}\right)^{\frac{10}{3}}$

$L_{10}=\left(\frac{C}{P}\right)^3$
$L_{10}=\left(\frac{C}{P}\right)^{\frac{10}{3}}