1projectile motion
y=xtan(theta)-(1/2)g^2cos^2(theta) =xtan(theta)*(1-(x/R)) =ax-bx^2 , a=tan(theta), b=g/2u^2cos^2(theta) ,a=R ,a^2/4b=H
2H and R relationship
4H=Rtan(theta)
3velocity at any time during the motion
vnet=√(u^2+g^2t^2-2ugtsin(theta)) tan(alpha) =usin(theta)-gtcos(theta)
4for same range equations
T1/T2=tan(theta) ,H1/H2=tan^2(theta) T1×T2=2R , H1×H2=R^2/16 , T1^2+T2^2=4Rmax ,H1+H2=Rmax/2
5net displacement
r,=√(x^2+y^2) x=ucos(theta)t y=usin(theta)t-(1/2)gt^2
6momentum at any time
pi=m(ucos(theta))i^+m(usin(theta))j^pf=m(ucos(theta))i^+m(usin(theta)-gt)j^ at maximum height ∆p=-musin(theta)j^
7horizontal projectile
x=ut y=1/2gt^2 y=(1/2)g x^2^2
8time of flight in horizontal projectile
T=√(2H)
9v in horizontal projectile
v=√((u^2)+(gt)^2) v=u/cos(alpha) alpha is angle b/w horizontal and resultant velocity
10number of steps
n=2u^2hb^2
11wmin whour and wmin/whour =?
wmin =2π/(60×60) whour=2π/(12×60×60) wmin/whour=12